Question

Three noncollinear points determine a triangle. How many triangles can be formed with 8 points, no three of which are collinear?
A. 56
B. 24
C. 336
D. 6720

Answer 1

u have to form subsets of three points out of the 8 given
so u have
\[ \large \binom{8}{3} \]
triangles

Answer 2

Yup. Exactly as ^ said.
\[nCr = \frac{n!}{(n - r)!r!}\]\[8C3 = \frac{8!}{(8 - 3)!3!}\]Can you finish it up?

Answer 3

no

Answer 4

harder

Answer 5

Well, the following is as far as I can get you...
\[8C3 = \frac{\cancel{8!}}{\cancel{5!}3!} \implies \frac{8 \times 7 \times 6 }{3 \times 2 } \implies?\]

Answer 6

56

Answer 7

Yup :)

Answer 8

thanks

Answer 9

np :)

Answer 10

This was posted an hour ago but I'm just now receiving a message.

Answer 11

lol