Question

What are the solutions of 5x2 + 2x – 8 = 0?

Answer 1

when u have a cuadratic equaion \(ax^2+bx+c=0\) the "easiest" way to solve it is using the cuadratic formula
\[ \large x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \]
can u do it?

Answer 2

first of all your picture is amazing.. and second of all no that's why i asked for help :[

Answer 3

in your equation u have a=5 b=2 and c=-8 then replacing in the formula u get
\[ \large x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=
\frac{-2\pm\sqrt{5^2-4\cdot5\cdot(-8)}}{2\cdot5} \]

Answer 4

ok so far?

Answer 5

yes im with you

Answer 6

great

Answer 7

now
\[ \large =\frac{-2\pm\sqrt{25+160}}{10}=\frac{-2\pm\sqrt{185}}{10} \]

Answer 8

ok, thank god i'm understanding...

Answer 9

this is it

Answer 10

u have two solutions
\[ \large x_1=\frac{-2+\sqrt{185}}{10}\qquad\text{and}\qquad
x_2=\frac{-2-\sqrt{185}}{10} \]

Answer 11

did u get all this?

Answer 12

yes is that it?

Answer 13

yeah
u can use a calculator to compute \(\sqrt{185}\) if u need it
but that is it

Answer 14

thak you very much i understand this now :[)!

Answer 15

great
u r w