Find the standard deviation. Round to one more place than the data. 6, 5, 9, 13, 18, 7, 5, 20, 11, 15
A. 5.4
B. 1.2
C. 4.9
D. 5.1
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OpenStudy (anonymous):
first find the mean
\[\large x=\frac{6+5+9+13+18+7+5+20+11+15}{10}=10.9\]
now for standard deviation
\[\Large \sigma=\sqrt{\frac{1}{n}\Sigma _{j=1}^{n}(xj-x)^2}\]
OpenStudy (anonymous):
so using the above values can you find the standard deviation now ?
OpenStudy (anonymous):
standard deviation ?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
what is standard deviation
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OpenStudy (anonymous):
\[\Large \sigma=5.1\]
D
OpenStudy (anonymous):
@85295james
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
did you get it?
OpenStudy (anonymous):
no but i am thinking
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OpenStudy (anonymous):
ok let me explain in detail
OpenStudy (anonymous):
thank you
OpenStudy (anonymous):
are you okay with the mean ? 10.9 ?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
6+ 5+ 9+ 13+18+ 7+ 5+ 20+ 11+ 15 /10=10.9
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
but what do i do with 5.1
OpenStudy (anonymous):
i don't understand
OpenStudy (anonymous):
i am going to find the standard deviation
OpenStudy (anonymous):
did you get it now?
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