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Mathematics 12 Online
OpenStudy (anonymous):

In how many ways can the letters of the word 'permute' be arranged if: a) the first and last places are occupied by consonants? b) the vowels and consonants occupy alternate places?

OpenStudy (anonymous):

CVCVCVC--- this is the way letters should be arranged VCVCVCV--- there are only 3 vowels; so this order does not maintain vowel-constant in alternatre position. 3 vowels can be arranged in 3!/2! way (there are 2 E) = 3 4 constant in 4! way = 24

OpenStudy (anonymous):

so how do you work out part a?

OpenStudy (anonymous):

The first place needs a consonant. So 4 possibilities. The last place needs a consonant. So 3 possibilities. For the middle, 5! possibilities. I get 120 x 12 = 2400.

OpenStudy (anonymous):

the answer is 720 ways

OpenStudy (rsadhvika):

The first place needs a consonant. So 4 possibilities. The last place needs a consonant. So 3 possibilities. For the middle, 5! possibilities. (since 2 e's , divide 2!) you get (4*3) * 5!/2!

OpenStudy (anonymous):

Forgot the duplicates. You are right.

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