Determine the value of “n” so that the given condition is satisfied: One root of $16x^2 - 9x + n$ is three times the other.

Question

lgbasallote · Answer

let x-k be one factor...the other would be x - 3k

using remainder theorem

p(k) = 0
16(k)^2-9(k) + n =0
16k^2 - 9k + n = 0

p(3k) = 0
16(3k)^2 - 9(3k) +  n =0
16(9k^2) - 27k + n = 0
144k^2- 27k + n = 0


that's all i got lol

anonymous · Answer

lol...let's see what I can do now...

anonymous · Answer

144k^2 - 27k = 16x^2 - 9k
128k^2 - 18k = 0
k = 0
128k - 18 = 0
k = 9/64
Well, I just looked up the solutions...I was so close...

anonymous · Answer

I got 243/4096 and it turned out to be 243/256...interesting answer...

anonymous · Answer

Thanks lgba

anonymous · Answer

Oops posted wrong solution...

lgbasallote · Answer

lol i couldnt get *that* far...nice

anonymous · Answer

attachment