what is the DOMAIN of :
f(x) = (-cosx) / 2(rtsqr(1-sinx))

Question

what is the DOMAIN of :
f(x) = (-cosx) / 2(rtsqr(1-sinx))

anonymous · Answer

$$f(x) = \frac{-cosx}{2 \sqrt{1 - sinx}}$$

Here the terms inside the square toot must not be negative because square root of negative is not defined so:

$$\large 1- sinx \ge 0$$

Or:

$$sinx \le 1$$

Here x can take values for that sinx will not less than or equal to one this is the only condition here..

anonymous · Answer

just for completing waterineyes statement :

$\sin x≤1$  is true always...but ..we should consider the division by zero...so we must have 

$\sin x≠1$ so the domain is

$$R-\left\{ 2n\pi+\frac{\pi}{2} \right\} \ \ n=0,1,2,3,...$$

anonymous · Answer

wait what happens to the cos and 2?