use power rules to simplify (2xy^6)^5

Question

use power rules to simplify  (2xy^6)^5

zepp · Answer

Power rule:$$\LARGE y=x^n\\LARGE y'=nx^{n-1}$$

anonymous · Answer

$$\large  (2xy^6)^5 = (2)^5 \cdot (x)^5 \cdot (y^6)^5$$

parthkohli · Answer

Why do we have to make it so complicated?

zepp · Answer

Power of a power rule:$$\LARGE (x^a)^b=x^{a*b}$$

lgbasallote · Answer

i think by power rule she meant $$\huge (ab)^m = a^m b^m$$

parthkohli · Answer

Distribute 5 into all the exponents.

anonymous · Answer

$$\huge (y^a)^b = y^{ a \times b}$$

parthkohli · Answer

$(xy)^z = x^z \times y^z$

lgbasallote · Answer

zepp · Answer

People, stop flooding/spamming and the most important.. stop repeating what I've typed .. .-.

anonymous · Answer

im still at a loss here

zepp · Answer

And I'm pretty sure the asker could easily figure out what to do with the only two hints I typed.

anonymous · Answer

i wish that was true

lgbasallote · Answer

check the link i posted...i gave an explanation to it already

anonymous · Answer

ty

zepp · Answer

The first thing to do is to simplify it, then you take the derivative with the power rule.

anonymous · Answer

ty

lgbasallote · Answer

@zepp this is an algebra question...not a calculus one

zepp · Answer

Oh

zepp · Answer

Power rule sounds pretty Calculus to me.

lgbasallote · Answer

and for yur question why the explanations are being repeated..it's because everyone's so competitive