Question

Find all the values of t between 0 and 2pie for which sec(2t-1) = 1.25

Answer 1

Now take \(\cos^{-1}\) (also known as \(\arccos\))

Answer 2

Am I right?

Answer 3

something looks wrong :)
\[ \frac{1}{cos(2t-1)} = 1.25\]
your use of notations is wrong :)

Answer 4

Oopsie

Answer 5

you cant say \(sec^{-1}\)

Answer 6

or \(cos^-1\)

Answer 7

I am still a learner, sorry.

Answer 8

\(1 = 1.25 \cos(2t - 1)\)
\[ 0.8 = \cos(2t - 1) \] Now is that correct?

Answer 9

you should know what \(cos^{-1}x\) is
you are NOT allowed to say \(cos^{-1}\)

Answer 10

Hmm. I just meant 'taking arccos'

Answer 11

inverse functions are different dont be confused :)

You are indeed right now.

Answer 12

in mathematics terminology you cant say it like that

Answer 13

Thank you!

Answer 14

\(secx\) is NOT \(cos^{-1}\)

Answer 15

\( \arccos(0.8) = \arccos{(\cos(2t - 1))}\)

Answer 16

no no

Answer 17

Oh

Answer 18

I need to open my own question before I spoil this one up.

Answer 19

\[(2t-1) =arccos(0.8)\]

Answer 20

@Omniscience
and what is \[\cos^{-1}\]??

Answer 21

@ParthKohli: used it wrongly :)
that is not right.
\[secx = \frac{1}{cosx}\]
you CANNOT say its \(cos^{-1}\) it just doesnot exist :)

Answer 22

@Omniscience By \(\cos^{-1}\), I meant 'arccos', not \(1 \over \cos\)

Answer 23

well for inverse trig symbols like \(cos^{-1}\) are not allowed to stand alone because they do not make sense :)

if you are referring to \(arccos\) then its fine guess but can be confusing in mathematics; better not to use it often :)

Answer 24

Haha :)

Answer 25

Now ! I agree ! @Omniscience
Thank you !

Answer 26

:)

Answer 27

so there is a prob with the question?