Question

find the values for the trigonometric functions of t from the given information. tant= -3/4, cost >0

Answer 1

i'll let my assistant @waterineyes take this one :)

Answer 2

Do you want to find cost sint cott etc etc all the values @tamy

Answer 3

yes, all those values. thanks for helping =]

Answer 4

So we have to use some identities here;

\[\large \sin^2 \theta + \cos^2 \theta = 1\]

\[\large \cot \theta = \frac{1}{\tan \theta}\]

\[\large 1 + \tan^2 \theta = \sec^2 \theta\]

Answer 5

I think they will be sufficient for the solution..

Answer 6

my assistant is very good :DDD haha lol

Answer 7

Now let us find sec(t) from the third identity I gave you..

\[\large \sec^2(t) = 1 + (\frac{-3}{4})^2 \implies 1 + \frac{9}{16} \implies \frac{25}{16}\]

So now take the square root:

\[\large \sec(t) = \frac{5}{4}\]

Getting till here @tamy

Answer 8

And you know:

\[\large \cos(t) = \frac{1}{\sec(t)} \implies \frac{1}{\frac{5}{4}} \implies \cos(t) = \frac{4}{5}\]

Answer 9

Now using first identity I gave you:

\[\large \sin^2 (t) = 1- \cos^2 (t) = 1 - (\frac{4}{5})^2 = 1 - \frac{16}{25} \implies \frac{9}{25}\]

Now take the square root:

\[\large \sin(t) = \frac{3}{5}\]

Answer 10

Can you do further or not ?? @tamy

Answer 11

yes I think I got it. Thank u so much!

Answer 12

For your easiness I explain you more:

\[\large cosec(t) = \frac{1}{\sin(t)}\]

By using this find cosec(t)..

\[\large \cot(t) = \frac{1}{\tan(t)}\]

By using this find cot(t)..

Answer 13

@tamy try it once and if you have problem then let me know..

Answer 14

I will if I do. u are very helpful thanks =]

Answer 15

Welcome dear..