Question

Using the elimination method how to solve the value of x and y. -6x-y=29 / 8x+3y=-47

Answer 1

multiply the first equation by 3 to give
-18x - 3y = 87 now add the first one to eliminate y:
8x + 3y = -47

Answer 2

this gives an equation in x which you can solve

Answer 3

then plug the value of x in the original first equation to find y

Answer 4

first to eliminat x mul ist equation with coefficient of x in 2nd term
2nd equation with coefficient of x in 1st term
now add terms or subtract to get value of x

Answer 5

How about using the substitution and comparison method? using the same given example

Answer 6

now put value of y in 1st or 2nd term to get valu of x

Answer 7

For substitution method:

Find the value of y from first and then put it into second to get x..

Answer 8

first to eliminat x mul ist equation with coefficient of x in 2nd equation
2nd equation with coefficient of x in 1st euation
now add or subtract 2 equations to get value of x
now put value of y in 1st or 2nd equation to get value of x

Answer 9

multiply the first equation by 3 on both sides
-18x - 3y = 87
now add the first equation to this equation to eliminate y:
-18x - 3y = 87
8x + 3y = -47
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u try next steps

Answer 10

then plug the value of x in the first or second equation to find y

Answer 11

I'm a little confused on how to get the value of y.

Answer 12

-18x - 3y = 87
8x + 3y = -47
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-10x=40
x=-4
now put in 2nd equation
8(-4) + 3y = -47
3y=-47+24
3y=-23
y=-23/3