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what is the LCM of (x+3)and (x^2-9)
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Factorize the (x^2 - 9) first..
\(x^2 - 9 = (x + 3)(x - 3)\)
\[(a^2 - b^2) = (a+b)(a-b)\]
(x+3)(x-3)
\(x + 3\), \((x + 3)(x - 3)\). Now it's just oral.
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Now take the LCM.. One common factor and one non common factor will be the LCM..
The common factor is \(x + 3\). The factors that are not common = LCM.
I mean, common * uncommon
(x+3)(x-3)??
Well Done..
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THANKS!!
That's right!
Welcome dear..
:)
\(x + 3 \times x - 3 = x^2 - 9\) \(x^2 - 9 \times 1 = x^2 - 9\) Confirmed
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lcm is the common tern in 2 equations (a2−b2)=(a+b)(a−b) x2−9=(x+3)(x−3) now common terms of (x+3)and (x^2-9) common terms of (x+3)and (x+3)(x−3) is the lcm
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