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Given: \(a + b = 4\) \(a^3 + b^3 = 28\) What is \(a - b\)? I got this: \(a^3 + b^3 = (a + b)(a^2 - ab + b^2)\) \(28 = 4(a^2 - ab + b^2)\) How do I continue?
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you can simplify it further
\(7 = a^2 - ab + b^2\)
I completed it by guess and check, but I need to do it algebraically
\[a^2 - ab + b^2 = (a+b)^2 - 3ab\]
@Waterineyes, (a - b)^2*
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@waterineyes \[a^2 + b^2 -ab - ab = (a-b)^2 \ne (a+b)^2\]
\[\large{(a-b)^2=a^2+b^2-2ab}\] \[\large{a^2+b^2+2ab=16}\] \[\large{(a-b)^2=a^2+b^2+2ab-4ab=16-4ab}\]
\[(a + b)^2 - ab - ab =a^2 + b^2\]
|dw:1343568845818:dw|
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