What is the magnitude and direction of GH if G(3, -2) and H(6, 4)? magnitude: 6.71 units; direction 63.43° magnitude: 6.71 units: direction: 26.57° magnitude: 3.61 units; direction: 26.57° magnitude: 3.61 units: direction: 63.43°
first find the resultant vector what is it?
im not sure what that is
it's the same thing you just did; subtract the final coordinates from the initial ones
v=<xh-xg,yh-yg>
oh right, i thought this was solved a different way.
we will have to do more, but the first step is finding the vector components
ok, the components are <3,6>
ok, so the magnitude (length) for a vector is found using the pythagorean theorem on its components
could i use the distance formula?
|dw:1343580631354:dw|\[\vec v=\langle x,y\rangle\]the magnitude is\[\|\vec v\|=\sqrt{x^2+y^2}\]
if that is what you mean by the distance formula (hopefully you can see how they are related)
and for the angle we use a little trigonometry I presume you have taken or are taking trig, right?
this is actually geometry
how to calculate the angle ?
I know to calculate the angle with trig|dw:1343580920560:dw|\[\tan\theta=\frac yx\implies\theta=\tan^{-1}\frac yx\]but with pure geometry I guess we have to do some reasoning about the fact that the y component is twice as long as the x component
which trig function would we use for this?
tangent, (which leads to inverse tangent) as I wrote above
ok, i got the magnitude. 6.71
|dw:1343581180531:dw|
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