Question

How do you find a polynomial function with a real and imaginary root, like (x-11)(x-2i); do you just use the distributive property? Also, can 6i/3 be simplified to 2i?

Answer 1

6i/3 can indeed be simplified to 2i.
If a polynomial function has complex roots, then these roots always appear in pairs - where each pair is the complex conjugate of the other.

Answer 2

so, in your example, if one of the roots was 2i, then -2i will also be a root.
So lets say the roots of your polynomial were 11, 2i and -2i, then your polynomial would be:\[(x-11)(x+2i)(x-2i)=(x-11)(x^2+4)\]

Answer 3

Alright C: well, thanks

Answer 4

yw :)