Look at the figure.
What is the length of AB?
27 cm
33 cm
34.32 cm
24.32 cm
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OpenStudy (anonymous):
post the image please
OpenStudy (kylav210):
OpenStudy (campbell_st):
you need the tan ratio...
and fine the lengths AP and PB
\[\tan 30 = \frac{10}{AP}\]
\[\tan(450 = \frac{ BP}{7}\]
then its AP + BP = AB
OpenStudy (anonymous):
\[\tan(\theta) = \frac{Perpendicular}{Base}\]
\[\tan(30) = \frac{10}{AP} \implies AP = 10 \sqrt{3}\]
\[\tan(45) = \frac{7}{PB} \implies PB = 7\]
Just add them now:
\[\implies 10 \sqrt{3} + 7 = ??\]
OpenStudy (kylav210):
24.32??(:
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OpenStudy (anonymous):
I am just kidding..
Ha ha..
OpenStudy (kylav210):
Lol thats okay!(:
OpenStudy (anonymous):
Yes you are right @kylav210
OpenStudy (kylav210):
Yay! Thank you(:
OpenStudy (anonymous):
Welcome dear..
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OpenStudy (kylav210):
One more question??
The figure below shows a circular prop with two triangles labeled ABC and AOC made on it. The center of the prop is labeled O.
What is the area of the cloth required to make the circular prop?
12.56 ft2
3.14 ft2
6.28 ft2
10.32 ft2
OpenStudy (kylav210):
@waterineyes
OpenStudy (anonymous):
Not sure but use pythagoras theorem:
\[\large r^2 + r^2 = 2^2 \implies r^2 = 2 \implies r = \sqrt{2}\]
r is the radius here..
OpenStudy (anonymous):
So to find the area of circle use:
\[Area = \pi r^2 \implies (3.14) \times (2) = ??\]
OpenStudy (kylav210):
6.28!? (:
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