A bacteria culture will grow from 400 to 5000 in 1 1/4 hours.
a) Find the constant k for this bacteria using growth formula, y=ne^kt, and write the growth equation.
b)Use your equation to predict how much longer it will take the 5000 bacteria to become 15000 bacteria.
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OpenStudy (anonymous):
\[y=ne^{kt}\]
OpenStudy (anonymous):
n is beginning
y is end
OpenStudy (anonymous):
Correct. Dont know where to start on this problem.
OpenStudy (anonymous):
so in beginning there was 400
OpenStudy (anonymous):
so plug in 400 for n
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OpenStudy (anonymous):
plug in what for y?
OpenStudy (anonymous):
5000?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
\[5000=400 e^{kt}\]
OpenStudy (anonymous):
t represent time , what time do you see there
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OpenStudy (anonymous):
t would go in as 1.5
OpenStudy (anonymous):
1 1/4= 1.25
OpenStudy (anonymous):
I knew that.
OpenStudy (anonymous):
let's go with that
OpenStudy (anonymous):
k. so the equation is
\[5000=400e ^{k(1.25)}\]
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
your job is to find k
OpenStudy (anonymous):
Hmm...take ln of both sides and bring exponent down then solve for k?
OpenStudy (anonymous):
exactly
OpenStudy (anonymous):
\[\ln(5000)=k(1.25)\ln400e\]
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OpenStudy (anonymous):
not what I would do
OpenStudy (anonymous):
How would you set it up?
OpenStudy (anonymous):
I would divide both sides by 400 first
OpenStudy (anonymous):
Ohh okay.
OpenStudy (anonymous):
\[5000/400=e ^{k(1.25)}\]
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OpenStudy (anonymous):
now take ln of both sides
OpenStudy (anonymous):
\[\ln(25/2)=k(1.25)lne\]
OpenStudy (anonymous):
Wouldnt ln and e cancel eachother out though?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
So basically, to get k, you would divide ln(25/2) by 1.25?
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
k=2.02?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
lol thanks. so to rewrite the equation, i would just plug everything in?
OpenStudy (anonymous):
\[5000=400e ^{2.02(1.25)}\]
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OpenStudy (anonymous):
close but to be more general you use t instead of specific time
OpenStudy (anonymous):
Ohh okay. So intead of 1.25, just t?
OpenStudy (anonymous):
\[y=400e ^{2.02(t)}\]
OpenStudy (anonymous):
that way you can find y for any t value you plug in
OpenStudy (anonymous):
So on b, you would plug n as 5000 and y as 1500?
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OpenStudy (anonymous):
*15000
OpenStudy (anonymous):
exactly , this time you are finding the 't'
OpenStudy (anonymous):
I got 0.5438
OpenStudy (anonymous):
Because you divide by 5000 on both sides.
Getting:
\[\ln(3)=(2.02)\ln(e)\]
OpenStudy (anonymous):
And then divide by ln(2.02)
Did I do it right?
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
Thank God. lol. But would that be like 5 mins?
OpenStudy (anonymous):
what?
OpenStudy (anonymous):
.5438
OpenStudy (anonymous):
yes ,
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OpenStudy (anonymous):
it will take .5438 hours
OpenStudy (anonymous):
okie dokes.
OpenStudy (anonymous):
Thanks youuuu!!
OpenStudy (anonymous):
nice to meet you
OpenStudy (anonymous):
Nice to meet you too. It was good working with you.