Mathematics
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OpenStudy (anikate):
find the exact value of cos(135) and sin(135)
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OpenStudy (anikate):
@Calcmathlete
OpenStudy (anikate):
@ahaines14 @seattle12345 @sami-21 @Callisto
OpenStudy (anikate):
@Calcmathlete
OpenStudy (anikate):
help!
OpenStudy (anikate):
calling all units we need help on math
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OpenStudy (anikate):
hellp me
OpenStudy (anonymous):
lol...it's called the unit circle.
OpenStudy (anikate):
wait
OpenStudy (anonymous):
Do you remember the values for it?
OpenStudy (anikate):
how do we find out without using the unit circle?
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OpenStudy (anonymous):
Your back!
OpenStudy (anikate):
what's on my back?
OpenStudy (anonymous):
Not really any other way at this point. A bit of advice, you probably should memorize the unit circle, or at least Quadrant I.
OpenStudy (anikate):
can you plz post it
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OpenStudy (anonymous):
Got it?
OpenStudy (anikate):
how do I figure it out with the unit circle?
OpenStudy (anonymous):
cosine is the x-value and sine is the y-value.
OpenStudy (anonymous):
Its 2 root 2, isnt it?
OpenStudy (anonymous):
With a hypotenuse of 1
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OpenStudy (anikate):
what does that mean calc?
OpenStudy (anonymous):
\[\cos 135º = -\frac{\sqrt{2}}{2}\]\[\sin 135º = \frac{\sqrt{2}}{2}\]
OpenStudy (anonymous):
Basically, the coordinates for 135º on the unit circle is \[(-\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2})\]cosine is the x-value and sin is the y-value.
OpenStudy (anonymous):
right, because it is in the second quadrant, and you have to go back.707, then up .707
OpenStudy (anonymous):
Thats how I think of it
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OpenStudy (anonymous):
Yeah. Also, @Topkart33 usually when you use the unit circle, you don't use a calculator because that defeats the purpose of using it..
OpenStudy (anikate):
will it always be cos and sin only
what about tan?
OpenStudy (anonymous):
Remember that \[\tan = \frac{\sin}{\cos}\]
OpenStudy (anonymous):
Right, it just gives me a perspective of what the traingel looks like in relationship to where it is on the circle, I know it is root 2/2
OpenStudy (anonymous):
triangle*
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OpenStudy (anikate):
is there a numonis device to remember all the formulas?
OpenStudy (anonymous):
For the sin, cos, and trig part?
OpenStudy (anonymous):
*tan
OpenStudy (anikate):
no for sn=a1(n^r-1) etc.
OpenStudy (anikate):
calcmath what time is it in your place?
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OpenStudy (anonymous):
ok lets do it
\[\Large \cos(90+45)=-\sin(45)=-\frac{1}{\sqrt{2}}\]
OpenStudy (anonymous):
Well, I don't have one for the sequences and series ones, but I never really needed it :/ It is 10:28
OpenStudy (anikate):
oh same here
OpenStudy (anonymous):
now for sin
\[\Large \sin(90+45)=\cos(45)=\frac{1}{\sqrt{2}}\]
OpenStudy (anikate):
cos is x and is y, right?
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OpenStudy (anonymous):
@Anikate did you get it ?
OpenStudy (anikate):
and sin is y right?
OpenStudy (anonymous):
10:28 PM?
OpenStudy (anonymous):
Now 10:31pm, yeah that is the proof of it
OpenStudy (anonymous):
@Anikate ??
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OpenStudy (anikate):
cos is x and sin is y right?
OpenStudy (anikate):
someone answer me
OpenStudy (anonymous):
Yes. cos is x and sin is y.
OpenStudy (anonymous):
@Anikate what is the Question can you elaborate ? i did not get your question
you want to find the values of sin(135)
and cos(135)
correct?
OpenStudy (anonymous):
Do you understand? You can also work it out if you want.
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