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Is x^(2)y' + e^(x)*y=4 a differential equation that is linear?
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Yes, it is linear.
it goes to: (dy/dx)x^2 + ye^(x) = 4
right?
and then you divide both sides by x^2?
yes
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ahh i see. do i divide ye^(x) by x^2 as well?
yes then you have to find the integrating factor
oh okay, i got it, thanks guys!
\[x^2y' + e^x y=4\] \[y' + \frac{e^x}{x^2} y=\frac{4}{x^2}\] This is linear because it is of the form; \[y'+p(x)y=q(x)\] Where \( p(x)= \frac{e^x}{x^2}\) \(q(x)=\frac{4}{x^2}\)
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