A train needs 20 seconds to go through a 100 yard tunnel. The very same train going at a constant speed needs 50 seconds to go through a 330 yard tunnel. What is the length of the train?
you need to setup two equations... which part you need help with ?
call, length of train = x speed of trian = s
actually...it's doable with one equation only
use the relation, distance = speed*time
since speed is constant
hmm
something like distance/time = distance/time
Is the speed of train in both cases is equal? I mean it is given r nt?
r=or*
this question needs a clarification.
100+x = 20*s --------(1) 330+x = 50*s--------(2)
something like this \[\huge \frac{100 + L}{20} = \frac{330 + L}{50}\]
where L is length of train
you guys do the rest ;)
oh..
But my doubt is other @lgbasallote :/
proportions are cute :D
I think we can't take same speed in both cases as it is nt stated.
speed is constant...that means speed is the same at both instances
speed is constant in second case only but wt about the first case. question needs a clarification.
*sigh*
im not willing to do a grammar tutorial right now
but it is a type of physics question too physics do nt recommend this @lgbasallote ur solution is right 100% but question need clarification @CosmicStorm :/
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