What is the sum of the multiples of 3 between 3 and 999, inclusive?
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Brendas wants a detailed solution!
Actually she only wants answers not how to solve this..
How many numbers are we talking about. From 1 to 1000 is 1000. Leaving out 1, 2, 3 and 1000, we have 996. Don't worry, I'll put the 3 back in a minute. Every third intgeer from 4 to 999 is a mulitple of 3. Divdiing 996 by 3 gievs 332. Putting the 3 back menas 333 multpiles of 3. Looking at the sum of the fisrt few, we have 3 + 6 + 9 + 12 + ... Which is 3 tiems the sum of 1 + 2 + 3 + 4 + .. Now for that hadny-dadny sum of the fisrt n integers: \[(1/2)(n)(n + 1). \] We're summing from 1 to 333, so the sum is\[ (1/2)(333)(334) = 55611 \] now multiply that by 3. 166833 is the sum of all the multiples of 3 between 3 and 999, inclusive.
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