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Mathematics 7 Online
OpenStudy (anonymous):

Find the surface area of the right triangular prism below.

OpenStudy (anonymous):

OpenStudy (lgbasallote):

first try and solve for the hypotenuse...what do you get?

OpenStudy (anonymous):

how do you do that?

OpenStudy (lgbasallote):

\[c = \sqrt{a^2+b^2}\] remember that thing?

OpenStudy (anonymous):

oh, yes! so do i plug in 3, 4 and 8 into that so 8= sqroot 3sq+4sq

OpenStudy (lgbasallote):

no...

OpenStudy (lgbasallote):

8 is not part of the right triangle

OpenStudy (lgbasallote):

you're going to look for that last side of the triangle

OpenStudy (lgbasallote):

only then can you solve tis

OpenStudy (anonymous):

oh. i get it now 3sq +4sq=csq

OpenStudy (lgbasallote):

yup

OpenStudy (lgbasallote):

so solve for c

OpenStudy (anonymous):

its 5, now what?

OpenStudy (anonymous):

To find the surface area of a right triangular prism we must use this formula: SA = wh + lw + lh + ls w = width h = height l = length s = side now find hypoteneus of triangle 3^2 +5^2 = h^2 hyp will be 5 ad now plug values

OpenStudy (lgbasallote):

\[SA = h(a+b+c) + ab\]

OpenStudy (lgbasallote):

where a = 4 b = 3 c = 5 h = 8

OpenStudy (anonymous):

108!

OpenStudy (lgbasallote):

seems so

OpenStudy (anonymous):

could you help me with another one? please

OpenStudy (lgbasallote):

hmm ill try

OpenStudy (anonymous):

Find the value of x in the figure below if the volume is 232,789.58 mm3.

OpenStudy (lgbasallote):

use the formula \[V = \frac{bah}{2}\] where b (base) = 24.5 a (altitude) = what you're looking for h (height) = 75.4 v = volume

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