Find the surface area of the right triangular prism below.
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OpenStudy (anonymous):
OpenStudy (lgbasallote):
first try and solve for the hypotenuse...what do you get?
OpenStudy (anonymous):
how do you do that?
OpenStudy (lgbasallote):
\[c = \sqrt{a^2+b^2}\]
remember that thing?
OpenStudy (anonymous):
oh, yes! so do i plug in 3, 4 and 8 into that
so 8= sqroot 3sq+4sq
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OpenStudy (lgbasallote):
no...
OpenStudy (lgbasallote):
8 is not part of the right triangle
OpenStudy (lgbasallote):
you're going to look for that last side of the triangle
OpenStudy (lgbasallote):
only then can you solve tis
OpenStudy (anonymous):
oh. i get it now 3sq +4sq=csq
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OpenStudy (lgbasallote):
yup
OpenStudy (lgbasallote):
so solve for c
OpenStudy (anonymous):
its 5, now what?
OpenStudy (anonymous):
To find the surface area of a right triangular prism we must use this formula:
SA = wh + lw + lh + ls
w = width
h = height
l = length
s = side
now find hypoteneus of triangle 3^2 +5^2 = h^2
hyp will be 5 ad now plug values
OpenStudy (lgbasallote):
\[SA = h(a+b+c) + ab\]
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OpenStudy (lgbasallote):
where a = 4
b = 3
c = 5
h = 8
OpenStudy (anonymous):
108!
OpenStudy (lgbasallote):
seems so
OpenStudy (anonymous):
could you help me with another one? please
OpenStudy (lgbasallote):
hmm ill try
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OpenStudy (anonymous):
Find the value of x in the figure below if the volume is 232,789.58 mm3.
OpenStudy (lgbasallote):
use the formula \[V = \frac{bah}{2}\]
where b (base) = 24.5
a (altitude) = what you're looking for
h (height) = 75.4
v = volume