Question

x^2-4x+4=49

Answer 1

\[x^2 - 4x - 45 = 0 \]Now factor!\[x^2 - 9x + 5x - 45 = 0 \]

Answer 2

\[x(x-9) + 5(x-9) = 0\]Can you solve from here?

Answer 3

ahh..... so either -5, or 9

Answer 4

\[\huge \checkmark\]

Answer 5

:)

Answer 6

to solve this we need to put it in the form of ax^2 + bx +c = 0 form then after that we may apply the formula to factor this problem down or use product sum method or any method that you are familar with to factor. so therefore in this case we got

x^2 -4x + 4 - 49 = 0 --> x^2 - 4x -45 =0 so in this case our product is -45 and sum is -4 and our two numbers are -5, 9 hence (x-5)(x+9) = 0 hence x=5 or x=-9 :)

Answer 7

or you can just do this to make lives easier
\[x^2 - 4x + 4 = 49\]
\[\implies (x-2)^2 = 7^2\]
\[\implies \sqrt{(x-2)^2} = \sqrt{7^2}\]
\[\implies x-2 = \pm 7\]
\[\implies x = \pm 7 + 2\]
therefore x = 9; x = -5