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9x^2+30x+25=64
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A good start is subtracting 64 from both sides.\[ \color{Black}{\Rightarrow 9x^2 + 3x + 25 - 64 = 0}\] Simplify, and solve the quadratic equation.
the 9x^2 is what I am confused about.
confused ??
u can solve it by factorization...
(9x^2+3x)(25-64)
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9x2+30x+25=64 9x2+30x+25-64 = 0 9x2+30x-39 = 0 9x2 -9x + 39x -39 = 0 9x(x-1) +39 (x-1) = 0 (9x +39) (x-1) = 0 so, x = -39/9 and x =1....
sorry, but I do know the answer involves imaginary numbers.
Actually no... The solutions for x as an answer does not involve imaginary #'s, and it's not 59/3
@Ganpat is correct.
ah..so my answer was wrong...sorry
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With the imaginary line, it's the intersection: |dw:1343664593480:dw|
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