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quyz i need a prove for derivative of the sum or difference of two function
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d(u + v) /dx = du/dx + dv /dx ??
We know derivative is defined as \[f'(x)=\lim_{h \to 0} \frac{f(x+h)-f(x)}{x+h-x}=\lim_{h \to 0} \frac{f(x+h)-f(x)}{h}\]
suppose f(x)=g(x)+r(x) so \[f'(x)=\lim_{h \to 0} \frac{g(x+h)+r(x+h)-g(x)-r(x)}{x+h-x}\] let's rearrange a little \[f'(x)=\lim_{h \to 0} \frac{g(x+h)-g(x)+r(x+h)-r(x)}{h}\]\[=\lim_{h \to 0} \frac{g(x+h)-g(x)}{h}+\frac{r(x+h)-r(x)}{h}=g'(x)+r'(x)\] Hence proved
thx too much @ash2326
you're welcome:D
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