Question

y=4/3x+15 solve by Identify the asymptotes.

Answer 1

Same thing as before. An asymptote is a limit where the line does not exist. So again, assuming the equation is \[y=(4/3x)+15\] an asymptote is at x=0 again. If the equation is \[y=4/(3x+15)\]
The asymptote is where the denominator is zero: so 3x+15=0 > x=-5.
Brackets are very important and can change the answer dramatically.