Indicate in standard form the equation of the line passing through the given point and having the given slope.
B(6, 2), m = -1/2
X + 2 y = _ _
Think you can help, @yummydum ?
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OpenStudy (anonymous):
@lgbasallote can you take this one...i gotta go :/
OpenStudy (anonymous):
oh @saifoo.khan :D
OpenStudy (saifoo.khan):
Use the formula:
y - y1 = m(x-x1)
OpenStudy (anonymous):
there u are :P
OpenStudy (lgbasallote):
just use the point slope form \[y - y_1 = m(x-x_1)\]
where m is the slope
x1 is the x coordinate
y1 is the y coordinate
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OpenStudy (saifoo.khan):
y - (2) = -1/2 (x - 6)
OpenStudy (lgbasallote):
\[\implies y -(2) = -\frac 12(x-6)\]
simplify to get the final answer
OpenStudy (lgbasallote):
note: standard form is \(ax^2 + bx + c = 0\)
OpenStudy (saifoo.khan):
o_O
OpenStudy (anonymous):
You guys are on this like flies! Hang on, I'll try solving it...
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OpenStudy (saifoo.khan):
Standard form:
ax + by = c
OpenStudy (anonymous):
Actually wait, I don't think you guys understand the question. I'm supposed to be filling in boxes to complete an equation, hence the "_" in the question.
OpenStudy (anonymous):
So @lgbasallote I think I might need more help on this.
OpenStudy (lgbasallote):
i'll let my assistant @saifoo.khan help you for now :)
OpenStudy (saifoo.khan):
@lgbasallote ;
standard form = ax2+bx+c=0 ?
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OpenStudy (saifoo.khan):
i gtg now. I'm heading to bed. ^_^
@lgbasallote
OpenStudy (lgbasallote):
lol bed at 6 am :p
OpenStudy (saifoo.khan):
5! ;)
OpenStudy (saifoo.khan):
Gnite.
OpenStudy (lgbasallote):
anyway @Sephichief plug in the values for \[y - y_1 = m(x-x_1) \] first
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OpenStudy (anonymous):
I did, and I got
y - 2 = m(x-6)
OpenStudy (lgbasallote):
what's m?
OpenStudy (anonymous):
Oh, whoops! That would be 1/2, so that makes it
y - 2 = 1/2(x-6)
OpenStudy (lgbasallote):
nope it's NEGATIVE 1/2
OpenStudy (lgbasallote):
\[y-2 = -\frac 12(x-6)\]
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OpenStudy (anonymous):
Oh, forgot about the negative sign
OpenStudy (lgbasallote):
now what is the denominator in this equation?
OpenStudy (anonymous):
That would be 2 I think.
OpenStudy (lgbasallote):
right. so multiply all terms by 2
OpenStudy (anonymous):
y - 4 = -1/2(x-12)
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OpenStudy (anonymous):
Then what?
OpenStudy (lgbasallote):
now you recheck what you did because you made a mistake :p haha
OpenStudy (lgbasallote):
here's a hint for you
\[y-1 = \frac 13 (x-1)\]
if i multiply all terms by 3 i will get
\[3y - 3 = 1(x-1)\]
\[\implies 3y - 3 = x - 1\]
OpenStudy (anonymous):
Silly geometry and your rules...alright, would that be:
2y - 4 = -12
OpenStudy (lgbasallote):
still no
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OpenStudy (lgbasallote):
it will be 2y - 4 = -(x-6)
OpenStudy (lgbasallote):
1/2 just cancels out
OpenStudy (lgbasallote):
so the parenthesis remains unchanged
OpenStudy (anonymous):
Oh, alright.
OpenStudy (anonymous):
Got it! The answer was x + 2y = 10. Thank you for your help!
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