4 cards are drawn at random and without replacement from a standard deck of 52 cards.What is the probability of atleast 2 kings ?

Question

anonymous · Answer

Wrong numbers before sorry

anonymous · Answer

Anyway first draw King at 1/13 right and not K and 12/13

anonymous · Answer

So the branch with a K on #1, then K on #2 is 3/51 for second card.
So that's 1/52 times 3/51 for that branch.

anonymous · Answer

I think it'll be too hard to do four branches.  Help?

zarkon · Answer

use combinations

anonymous · Answer

thanks for answering but i still dont get it

zarkon · Answer

have you used $${n\choose r}=\,_n C_r=\frac{n!}{r!(n-r)!}$$

before?

anonymous · Answer

nope i havent seen or used that before

zarkon · Answer

by the time you have reached a question like this you should have.

anonymous · Answer

@Zarkon the trouble I'm having is sampling without replacement..