Question

Algebra II Question!
Solve for k, given points (1, k) and (5, | k |) lie on a line that has a slope of 3/5 .
A) -3/10
B) -6/5
C) -3/20
D) Ø
E) NOTA

Answer 1

I would use vector geometry, with the given slope.

Answer 2

It's Algebra II :P

Answer 3

it's not in the title q-:

Answer 4

Now it is :P XD

Answer 5

*grins*

Answer 6

I would use the fact that since it has a slope that isn't infinity, \(|k|\neq k\). Hence, \(k\) must be negative.

Answer 7

Oh that makes sense...but all of the answer choices are negative, so I kind of assumed that...

Answer 8

Next up, that means that \[\frac{-k-k}{5-1}=\frac{-2k}{4}=\frac{3}{5}\]Solve for \(k\), and I get \[k=-\frac{6}{5}\]

Answer 9

I used \((-k)-k\) for the numerator since \(|k|=-k\) must be true since \(k\) is negative.

Answer 10

Oh. I get it now...I just for some reason tend to get confused when absolute value comes in...

Answer 11

Thank you :)

Answer 12

You're welcome.