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Mathematics 22 Online
OpenStudy (anonymous):

For the given cost function C(x)= 14400+800x+x^2 find: a) The cost at the production level 1750 b) The average cost at the production level 1750 c) The marginal cost at the production level 1750 d) The production level that will minimize the average cost e) The minimal average cost

OpenStudy (anonymous):

I have everything except for d and e which seems to be the most difficult. I keep searching online but have not seem to find the answer to my problem.

OpenStudy (anonymous):

I always skipped the explanations for these things but.. if x = production level C = cost at a given production level I know what to do

OpenStudy (anonymous):

Cool well can you help with d and e?

OpenStudy (anonymous):

Back

OpenStudy (anonymous):

Are my assumptions correct?

OpenStudy (anonymous):

Wait did you try answering it? I am new to this. This is my first time here.

OpenStudy (anonymous):

I just had a problem connecting the terms in the description of the problem with the equation. Not familiar with standard form

OpenStudy (anonymous):

if x = production level C = cost at a given production level I know what to do

OpenStudy (anonymous):

Oh well if this helps A) is 4476900, B) is 2558.23, C)4300

OpenStudy (anonymous):

Is it true that x = production level and that C(x) = cost? !!!!

OpenStudy (anonymous):

Yes it is true.

OpenStudy (anonymous):

Then what we want is the minimum of the cost as a function of production. That is obtained by taking dC/dx and setting it equal to 0. Are you OK with derivatives?

OpenStudy (anonymous):

the derivative of the first function i have that answer which is 2x+800

OpenStudy (anonymous):

x=-400 but when i plug it in and it says it is wrong

OpenStudy (anonymous):

Yeah. Production can't be < 0. Sit on your retriceall day, it's still 0.

OpenStudy (anonymous):

They removed my bad word somehow!

OpenStudy (anonymous):

It's not 0 plugged it in and it's wrong

OpenStudy (anonymous):

2 things: problem /answers are wrong I'm wrong get some help OK?

OpenStudy (anonymous):

Okay thanks for the help though

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