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OpenStudy (anonymous):
so the answer will be 0
OpenStudy (anonymous):
?
OpenStudy (anonymous):
do you understand what the "zero" of a function means?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
so what is the zero of log (5x) ?
OpenStudy (anonymous):
1
OpenStudy (anonymous):
no
OpenStudy (anonymous):
the zero of a function f(x) is the value x, such that f(x)=0
OpenStudy (anonymous):
log (5*1)=log 5 does not equal zero. so x=1 is not a "zero"
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OpenStudy (anonymous):
so there is no solution
OpenStudy (anonymous):
?
OpenStudy (anonymous):
@eseidl sorry my bad
but No exponent to which any base can be raised that gives 0.
so no x that log(x) = 0
OpenStudy (anonymous):
Again! I mean no p where e^p = 0
OpenStudy (anonymous):
@telliott99 your misunderstanding the nature of the logarithm. y=logx
take "antilog" of both sides. \[10^y=x\]set y=0.\[10^0=x\]\[x=1\]what's the problem?
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OpenStudy (anonymous):
I agree that there is no p such that \[e^p=0\]but this doesn't imply that there is no x such that\[\log_{a}x=0 \]If fact x=1 will give \[\log_{a}1=0 \]for any base a. Because,\[1=a^0\]
OpenStudy (anonymous):
Just tired and typing the wrong things. Apologies for causing confusion.