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fund the exact length of the curve y=e^x, from x between 0 and 3
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\[ \Large \int_0^3 \sqrt{1+e^{2x}}dx \] yes ?
thats part of the answer but you have to make a u substitution or two and possibly use partial fractions
I would start with a trig substitution, maybe this will lead nowhere but let e^x=tan alpha
will that help? \[ e^x= \tan \alpha \\ dxe^x = \sec^2{\alpha}d\alpha \longrightarrow dx=\sec^2\alpha \cot\alpha d\alpha \]
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