Question

Find the coordinates of the center and the length of the radius of the following circle.

(x + 3)2 + (y - 6)2 = 24

Center = (_,_)

Radius = _sqrt_

Answer 1

(-3, 6) radius is sqrt(24) = 4sqrt(6)

Answer 2

do you see how I did this? Just take the value of x-? for the x value of the center here ? = -3 and squareroot the RHS

Answer 3

\[(x-a)^{2}+(y-b)^{2}=r ^{2}\]If the equation of the circle is of this form, then the center is (a,b), which are opposite values to the values in the parenthesis and the radius is the square root of (r squared).

Center (a,b)
\[radius = \sqrt{r ^{2}}\]