Question

What is the solution set of |x + 3| > 7?

Answer 1

hint (i'll give a demonstration)

|2x + 1| > 3

solve for x in 2x + 1 > 3 and 2x + 1 < -3

when 2x + 1 > 3
2x > 3 - 1
2x > 2
x > 1

when 2x + 1 < -3
2x < -3 - 1
2x < -4
x < -2

therefore in this example

-2 < x < 1

does that help?

Answer 2

yes i will review..

Answer 3

or try.. :[

Answer 4

go for it :D

Answer 5

Actually, @lgbasallote, you made a mistake.

Answer 6

I'll let you find it

Answer 7

And @rayford, don't change the question after you've posted it. You make @lgbasallote's solution look foolish.

Answer 8

how could you lgbasallote??? i looked up to you! :{

Answer 9

actually that was a demo @Hero that wasnt teh question

Answer 10

@lgbasallote, your demo is still incorrect.

Answer 11

At least the final result is.

Answer 12

and yeah i saw my mistake =)))) i was thinking it was silly a while ago so i unconsciously changed my already right answer -_-

Answer 13

i shouldnt have changed it

Answer 14

have you seen the mistake @rayford ?

Answer 15

hmm...no

Answer 16

it's actually the conclusion..

i stated x > 1 (this is read as x is greater than 1)

and also x <-2 (read as x is less than -2)

and i made a conclusion that -2<x <1 (which is read x is greater than -2 but less than 1)

Answer 17

but anyway..if you ignore that...that's how to solve it :DDD

Answer 18

ok ill review..

Answer 19

i got the answer! its x>4. so easy lool

Answer 20

actually there should be 2 answers

Answer 21

x<-10

Answer 22

yup

Answer 23

may you please answer my ther question...thats the really hard one i cant do.