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Mathematics 16 Online
OpenStudy (anonymous):

What is the slope of the line shown on the graph?

OpenStudy (anonymous):

OpenStudy (waleed_imtiaz):

Do U know what are the co-ordinates the point U will use ?

OpenStudy (phoenixfire):

Use the slope equation: \[m = {{y_{2} - y_{1}} \over {x_{2} - x_{1}}}\] You have the points in the graph, so just substitute them into that equation.

OpenStudy (waleed_imtiaz):

In my view,, there are two points (-5,0) and (0,2).... NOw use the two-point form to get an equation... U will get the equation 2x-5y+10=0 Now convert this into slope-intercept form..... Seperate y on one side ... 5y=2x+10 now, y= 2/5 x + 2 .... okay..... NOw compare it with y=mx+c.... U will get m= 2/5 ..... c=2 which satisfies the diagram.... where m stands for slope....... Sorry If I am wrong.... But Thats what I have calculated.... Guide me If I had made a mistake......... Thank You., :)

OpenStudy (phoenixfire):

waleed_imtiaz at x=0, y is not 2. so the Y-intercept can't be 2.

OpenStudy (phoenixfire):

Two points in that graph are: (-2, 1) and (3, 3)

OpenStudy (waleed_imtiaz):

Oh. okay.. then please Can u explain how U get these two points......... ?

OpenStudy (anonymous):

@PhoenixFire is right..

OpenStudy (anonymous):

Just see for x and y coordinates where the points lie..

OpenStudy (phoenixfire):

@waleed_imtiaz The two points I said are because they have dots on them in the graph that was presented.

OpenStudy (waleed_imtiaz):

oh... yea..... I got it.... the two points should me (-2,1) and (3,3)

OpenStudy (waleed_imtiaz):

Now can we apply the same procedure as I did.........? two point form.. then convert it into slope-intercept form and get the slope....... ? or some other method ?

OpenStudy (phoenixfire):

Attempt it and see if you get the same answer as just using the gradient equation I said earlier.

OpenStudy (waleed_imtiaz):

the slope will be = 2/5 again...... What U say ?

OpenStudy (phoenixfire):

Yes the slope will be 2/5. Now you can put the slope and one of the points into y=mx+c and solve for c if you want to know the y-intercept.

OpenStudy (waleed_imtiaz):

If we use these two points to solve for the slope.we'll get slope=2/5(-5,0) and (0,2).... and if we use(-2,1) and (3,3), then also slope=2/5..... So I can conclude from this that these points are collinear and any two points can be used in order to get the slope that make up the line..... What do u say @phoenixfire?

OpenStudy (phoenixfire):

@waleed_imtiaz The problem with that is that (-5, 0) and (0, 2) are NOT on the line. They are close, but they are not.

OpenStudy (waleed_imtiaz):

Mmmm........

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