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Chemistry 8 Online
OpenStudy (lgbasallote):

For which of the following species are the intermolecular interactions entirely due to dispersion forces? A) C2H6 B) CH3OCH3 C) NO2 D) H2S E) CaNO3

OpenStudy (lgbasallote):

im thinking it would be the nonpolar molecule...so A?

OpenStudy (anonymous):

yup its A ...... because its non polar ..... we have hydrogen bonding in B, C and D

OpenStudy (anonymous):

thus instantaneous-induced dipole forces are present between non polar molecule :D

OpenStudy (lgbasallote):

c d and e dont have h-bonding o.O

OpenStudy (anonymous):

sorry //// C , D , and E are POLAR

OpenStudy (anonymous):

i misread the question :( //// but the answer is A

OpenStudy (anonymous):

when flourine , chlorine, oxygen and nitrogen are present in a non symetrical molecule ... then it is polar

OpenStudy (anonymous):

and polar molecule have permanent dipole

OpenStudy (anonymous):

THUS A IS 110 % correct

OpenStudy (lgbasallote):

idk how to prove c d and e are polar though

OpenStudy (lgbasallote):

how do i prove they are polar?

OpenStudy (anonymous):

you know something about dipole moment >????

OpenStudy (lgbasallote):

all i know is drawing lewis...and it seems tedious

OpenStudy (anonymous):

you know something about dipole moment >????

OpenStudy (lgbasallote):

yes i know dipole moment...somehow

OpenStudy (anonymous):

or relative electronegativity of elements

OpenStudy (lgbasallote):

when the directions of the electronegativity in the lewis cancel out then zero dipole moment

OpenStudy (anonymous):

FLORINE, CHLORINE AND OXYGEN .. are the MOST ELECTRONEGATIVE ELEMENT

OpenStudy (lgbasallote):

mmhmm

OpenStudy (anonymous):

NO2 is polar because it has a lone electron

OpenStudy (anonymous):

unbonded

OpenStudy (lgbasallote):

yeah...i figured that one out already :D

OpenStudy (anonymous):

H2S is polar because of 2 lone pairs

OpenStudy (lgbasallote):

H2S i think looks something like |dw:1343732893300:dw|

OpenStudy (anonymous):

yup its shape is bent

OpenStudy (lgbasallote):

calcium nitrate...idk how that looks

OpenStudy (anonymous):

you dont need the structure ..... just look at the oxygen ... secondly ... it is non symmetircal ... thus it must be polar

OpenStudy (lgbasallote):

hmm i see

OpenStudy (anonymous):

|dw:1343733005262:dw|

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