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Mathematics 17 Online
OpenStudy (anonymous):

Choose the correct slope of the line shown on the graph below. Please Explain

OpenStudy (anonymous):

OpenStudy (amistre64):

a simple method for the slope of a line that has been graphed like this is just to divide the y intercept by the x intercept

OpenStudy (amistre64):

an since the slope goes up hill from left to right; just drop the negative

OpenStudy (anonymous):

i know this but i dont have any corridnates just this question and picture and these options three halves two thirds −three halves −two thirds

OpenStudy (amistre64):

the grap gives you coords .....

OpenStudy (anonymous):

its just line though?

OpenStudy (amistre64):

yes; where does the line cross the y axis?

OpenStudy (anonymous):

-5

OpenStudy (amistre64):

good; -5 divided by; where does the line cross the x axis?

OpenStudy (anonymous):

look like 7?

OpenStudy (amistre64):

looks more like 7.5 to me

OpenStudy (amistre64):

-5/7.5 = ?? and since its going uphill from left to right, ignore the negative

OpenStudy (anonymous):

1.5?

OpenStudy (amistre64):

youre not adept at dividing are you ....

OpenStudy (anonymous):

what?

OpenStudy (anonymous):

:D

OpenStudy (amistre64):

5/7.5 is not 1.5

OpenStudy (amistre64):

there are other ways of course to determine the slope from the graph ....

OpenStudy (anonymous):

i could use the formula?

OpenStudy (amistre64):

find 2 consequtive places that the line hits a "corner"

OpenStudy (anonymous):

kk

OpenStudy (amistre64):

count how many boxes you ahve to move to get form one corner to the other. up/over

OpenStudy (amistre64):

i see it hitting corners at: (0,-5) and (3,-3)

OpenStudy (anonymous):

wait i think i can get answer give me a sec

OpenStudy (id21):

Take one point on line I choose x=3, y=-3 From line equation \[y=kx+b\] b is y point, where line crosses x axis, in this example b=-5 so put all in equation \[-3=3k-5\\3k=2\\k=2/3\] So slope is 2/3

OpenStudy (anonymous):

the answer is 2 over 3

OpenStudy (amistre64):

2 over 3 is good to me

OpenStudy (anonymous):

yay thanks =D

OpenStudy (amistre64):

youre welcome :) and good luck

OpenStudy (anonymous):

thanks :D

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