Question

Solve for x in the proportion x/x+12 = 1/x-1

Answer 1

u have
\[ \large \frac{x}{x+12}=\frac{1}{x-1} \]
then
\[ \large x(x-1)=1(x+12) \]
can u finish this?

Answer 2

um, well what do i do next?

Answer 3

it is cuadratic equation
\[ \large x^2-x=x+12 \]
u should be able to solve this
can u?

Answer 4

yeah

Answer 5

great! do it and tell me what u get
just to check

Answer 6

wait, so i should use the quadratic equation?

Answer 7

do it whichever way u want
(i) quadratic formula
(ii) complete the square
(iii) factoring

Answer 8

okay

Answer 9

for instance
\[ \large x^2-x=x+12 \]
\[ \large x^2-2x+1=12+1=13 \]
then
\[ \large (x-1)^2=13 \]
\[ \large x-1=\pm\sqrt{13} \]
\[ \large x=1\pm\sqrt{13} \]

Answer 10

this is completing the square
u should get the same if you use the formula

Answer 11

okay

Answer 12

i got x ≈ −2.61 and x ≈ 4.61

Answer 13

u r right

Answer 14

okay thanks

Answer 15

u r w

Answer 16

could you help me with another?