Question

Given 482 milliliters of a gas at 37 degrees Celsius and at 1.3 atmospheres, how many moles of gas are present? (The ideal gas constant is 0.0821 L · atm/mol · K.)

Answer 1

\[PV=nRT\]
\[(1.3 atm)(.482 L)=n(.0821 \frac{L atm}{mol K})(310.15 K)\]
solve for n