Question

http://i1155.photobucket.com/albums/p559/joyce100596/a.png

Answer 1

you Pythagorean theorem :)

Answer 2

set up an equation \[a^2+b^2=c^2\]\[(2x+3)^2+(4x+5)^2=c^2\]

Answer 3

does x=88.5

Answer 4

now square the parenthesis and then combine like terms then find the square root :) im sure you can carry on from here :)

Answer 5

(4x^2+12x+9)+(16x^2+40x+25)=c^2
20x^2+52x+34=c^2

Answer 6

take it from there :)

Answer 7

this is so hard :c

Answer 8

you Pythagorean theorem :)
?
What does that supposed to mean? @yummydum

Answer 9

LOL...i mean to write "use" :P

Answer 10

how do i find x though?

Answer 11

@saifoo.khan help please :P ...now im stuck too :D

Answer 12

Let me see..

Answer 13

k thanks :)

Answer 14

Make 2 equations.

Answer 15

OHHHH :O

Answer 16

that makes so much sense now :D

Answer 17

Sure it does. ;)

Answer 18

how?:c

Answer 19

@yummydum will rip this question in seconds now.. just sit and watch.

Answer 20

@saifoo.khan kaaay thank you c:

Answer 21

\[(2x+3)^2+(4x+5)^2=c^2\]\[(2x+3)^2+(3x+11)^2=c^2\] substitution property, since both equal c^2 they both equal eachother\[(2x+3)^2+(4x+5)^2=(2x+3)^2+(3x+11)^2\]subtract (2x+3)^2 from both sides \[(4x+5)^2=(3x+11)^2\]square the binomials \[(4x+5)(4x+5)=(3x+11)(3x+11)\]\[16x^2+20x+20x+25=9x^2+33x+33x+121\]combine like terms\[16x^2+40x+25=9x^2+66x+121\]now subtract the 25 \[16x^2+40x=9x^2+66x+96\]minus the 40x from both sides\[16x^2=9x^2+26x+96\]last minus the 16x^2
\[0=-7x^2+26x+96\]
factor the trinomial and tell me what you get :D

Answer 22

OMG! Really? @yummydum

Answer 23

@saifoo.khan what? :)

Answer 24

That explanation is huge.

Answer 25

is that bad? :\

Answer 26

i was just doing step by step so the viewer wouldnt get lost

Answer 27

No, it's great! here: \(\Huge ✪\)

Answer 28

LOL thanks for starting me a star collection :P :D

Answer 29

i got 24.8 (: