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Mathematics 14 Online
OpenStudy (anonymous):

@jim_thompson5910 so, if p → q and q → r then its ~p → r?

jimthompson5910 (jim_thompson5910):

if p → q and q → r then p -> r

jimthompson5910 (jim_thompson5910):

think of it as a chain

jimthompson5910 (jim_thompson5910):

starting at p gets me to q (p -> q) then going from q to r (q -> r) means that I can start at p and go to r directly (p -> q)

OpenStudy (anonymous):

okay thats what i thought in the ut i wasnt sure

jimthompson5910 (jim_thompson5910):

alright, I'm glad you're thinking the right thing

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