Question

What is the quotient: (72y3 + 12y2 - 30y) ÷ 6y

Answer 1

\[\LARGE \frac{72y^3 + 12y^2 - 30y}{6y} \implies \frac{72y^3}{6y} + \frac{12y^2}{6y} - \frac{30y}{6y}\]
does that help?

Answer 2

so would 5 be the quotient

Answer 3

no...it is very far from the answer...

Answer 4

oh

Answer 5

So let's just talk about this. Why did you say "so would 5 be the quotient"

Answer 6

because 30/6 is 5

Answer 7

OK, but there are three terms, all of them contribute to the answer

Answer 8

Let's just start with this.. Suppose you had -30 y / 6 y

Answer 9

it would be -5y

Answer 10

If you have y on the top (in the "numerator") and on the bottom in the denominator, you know you can cancel them right?

Answer 11

oh yea

Answer 12

So -30 y / 6 y equals ?

Answer 13

-5

Answer 14

Yes. And notice the minus sign. You were missing that before. OK?
Now we'll do the other two terms.

Answer 15

i got 12 and 2

Answer 16

Well, the first term has y^3 up top and and y below. So you're going to have y^2 left in the answer for that part.. Do you see that?

Answer 17

So maybe you are a little hung up on the x's and y's???

Answer 18

yes i see that so would it be 12y^2 + 2y - 5

Answer 19

OK. So you know the rules. Good. So the question is why did you give your very first answer? Did you just guess? Please tell me so I can help you.

Answer 20

i divided and cut each exponet down 1

Answer 21

Your very first answer was
so would 5 be the quotient

Answer 22

Never mind.
You know the rules
Do the division for numbers
Cancel exponents to reduce things like y^2/y
Do each term one at a time (separated by + and -)
You know what to do!

Answer 23

thanks for the help