A sample of gas occupies a volume of 482 mL at a temperature of 282 K. At what temperature will this sample of gas occupy a volume of 502 mL? Show all of the work used to solve this problem.

Question

anonymous · Answer

Use V1/T1 = V2/T2

anonymous · Answer

its not set up for it yet. Wouldn't i have to use PV=nRT first? to find the moles then use V1/T1=V2/T2?

anonymous · Answer

dont need to

can use this directly

its called Boyle's Law

anonymous · Answer

Would you show me how to? Please?

lgbasallote · Answer

$$PV = nRT$$
since pressure and moles are constant you can just cancel them
$$V = RT$$
$$\frac{V_1}{T_1} = R$$
$$\frac{482}{282} = R$$
$$R = 1.709$$

so now solve for T_2
$$\frac{V_2}{T_2} = 1.709$$
$$\frac{V_2}{1.709} = T_2$$
$$\frac{502}{1.709} = T_2$$
$$293.70 K = T_2$$
that's if you really want to use PV = nRT but boyle's law just states that when pressure and moles are constant then $$\frac{V_1}{T_1} = \frac{V_2}{T_2}$$

anonymous · Answer

Thank you so much both you. 
:) I appreciate it.