Question

Suppose 550.0 J of heat is added to a 111-g piece of aluminum at 21.0° C. What is the final temperature of the aluminum?
___° C

Answer 1

The specific heat of aluminum is about 910J/kg therefore:
\[Q=mcΔT=mc(Tf−Ti)\]\[550.0J=(0.111kg)(910J/kg)(Tf-21.0C)\]Now just solve for Tf.