Question

What quantum numbers specify these subshells?

Answer 1

4s
n = ?
l = ?

Answer 2

I don't understand your question

Answer 3

it give me 4s 4p 5d
and it ask for n=? and l= ?

Answer 4

of each

Answer 5

is N for nitrogen?

Answer 6

no N would be 2p3

Answer 7

these deal with Orbitals and Quantum numbers...not Nitrogen =.=

Answer 8

well an s orbital can hold 2 electrons, a p orbital can hold 6 and a D orbital can hold 10

Answer 9

ok so what's the value for n and l ?

Answer 10

not sure i hvae never had to figure out a term for n or i. If you could tell me what they want for those values I will do my best to figure it out.

Answer 11

I'm not sure either...they gave me those subscript 4s,4p and 5d and gave me some boxes to input answers for n and l (L)
btw: n:principal quantum number
l: angular momentum quantum number

Answer 12

ok i believe n = 4 for them all because when you go into the d orbital you subtract one line from it. I still am not sure about L yet

Answer 13

then it should be 0 for the s orbital, 1 for the p orbital, and 2 for the d orbital

Answer 14

i don't get it :(

Answer 15

ok for the sake of guessing, i've got it right lol

Answer 16

it seems like n= 4,4,5 and l= 0,1,2

Answer 17

but how is it 0,1,2 is what i don't get?

Answer 18

ok then in is just the first number in the shell, those numbers are fixed with s being zero, p being 1, and d being 2, f is 3.

Answer 19

huh, so it goes in order from s,p,d,f i guess?

Answer 20

yea

Answer 21

ok for next question it asking for Be, what is n,l,ml,ms of Be

Answer 22

well it's in the 2s2 shell so n=2, l=0 not sure of the rest of them

Answer 23

how you know it's 2 and 0 ?

Answer 24

because s=0,p=1,d=2,f=3 and n is just the first number that comes up

Answer 25

hmm it gave me a bunch of choices, and told me that I should pick 4 answers out of those choices since Be have 4 electrons. But i only see 3 answers have n=2 and l=0