Question

Solve: -3 = log3^x

Answer 1

first, take the antilog of both sides. What do you get?

Answer 2

what do u mean antlog

Answer 3

y=log x
to get rid of the "log", we take the following step:\[10^y=x\]This is what is meant by the antilog. It "undoes" the log function.

Answer 4

so there is no solution

Answer 5

show your steps?

Answer 6

actually I didn;'t see the exponent on your question. It is even easier. If you have\[\log_{}a^x=x \log_{}a \]by the property of the logarithm. so you should be able to solve yours for x quite readily.

Answer 7

what is log3^x?
log_3(x) or log_10(3^x) or ln(3^x)???

Answer 8

log3^x?=4.77

Answer 9

what? how can x equal something, what is the base of your log?

Answer 10

3

Answer 11

\[\log_{3}(x)? \]

Answer 12

I was assuming the question was\[\log_{10}3^x=-3 \]

Answer 13

1/27 = x

Answer 14

log_3(x) = -3
3^(-3) = x
1/27 = x

Answer 15

only use ^ for exponents. Its very confusing.

Answer 16

yes

Answer 17

so x=1/27

Answer 18

yes