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Mathematics 14 Online
OpenStudy (anonymous):

Can someone just show me how to do this please? As 390 g of hot milk cools in a mug, it transfers 30,000 J of heat to the environment. What is the temperature change of the milk? The specific heat of milk is 3.9 J/g·°C.

OpenStudy (anonymous):

heat transferred q, is\[q=mc \Delta T\]you have m=390, q=30,000, c=3.9. Plu in your values and solve for delta T.

OpenStudy (anonymous):

390 x 30,000 x 3.9 = 45,630,000 ?

OpenStudy (anonymous):

\[\Delta T= \frac{q}{mc}\]try it again

OpenStudy (anonymous):

I'm confused about the symbols

OpenStudy (anonymous):

ok. delta T is the change in temperature. This is what you are asked to solve for. q is the quantity of heat transferred. m=the mass of the sample. and c is the specific heat capacity of the substance.

OpenStudy (anonymous):

m = 390 right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

q = 30,000 and c = 3.9 then?

OpenStudy (anonymous):

you have to be a bit careful with q, the quantity of heat transferred. When heat leaves your sample q is negative. When heat enters your sample q is a positive quantity.

OpenStudy (anonymous):

so in this case, it's negative?

OpenStudy (anonymous):

yep. so we expect the temperature to decrease, since it is cooling off after all.

OpenStudy (anonymous):

Ohh okay... so how do I write the equation?

OpenStudy (anonymous):

I already gave you the equation. all you have to do is put in the numbers and solve.

OpenStudy (anonymous):

\[30,000 \div 390 x 3.9\]?

OpenStudy (anonymous):

yeah.\[\Delta T=\frac{30000}{(390)(3.9)}\]

OpenStudy (anonymous):

well, should be -30000/(390*3.9) but yeah

OpenStudy (anonymous):

-0.0507 ?

OpenStudy (anonymous):

no. make sure you use brackets around the denominator in your calculator

OpenStudy (anonymous):

-19.72 ?

OpenStudy (anonymous):

you should get -19.7 degrees. So the milk's temperature decrease by 19.7 degrees C

OpenStudy (anonymous):

thank you so much

OpenStudy (anonymous):

no problem :)

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