Can someone just show me how to do this please? As 390 g of hot milk cools in a mug, it transfers 30,000 J of heat to the environment. What is the temperature change of the milk? The specific heat of milk is 3.9 J/g·°C.
heat transferred q, is\[q=mc \Delta T\]you have m=390, q=30,000, c=3.9. Plu in your values and solve for delta T.
390 x 30,000 x 3.9 = 45,630,000 ?
\[\Delta T= \frac{q}{mc}\]try it again
I'm confused about the symbols
ok. delta T is the change in temperature. This is what you are asked to solve for. q is the quantity of heat transferred. m=the mass of the sample. and c is the specific heat capacity of the substance.
m = 390 right?
yes
q = 30,000 and c = 3.9 then?
you have to be a bit careful with q, the quantity of heat transferred. When heat leaves your sample q is negative. When heat enters your sample q is a positive quantity.
so in this case, it's negative?
yep. so we expect the temperature to decrease, since it is cooling off after all.
Ohh okay... so how do I write the equation?
I already gave you the equation. all you have to do is put in the numbers and solve.
\[30,000 \div 390 x 3.9\]?
yeah.\[\Delta T=\frac{30000}{(390)(3.9)}\]
well, should be -30000/(390*3.9) but yeah
-0.0507 ?
no. make sure you use brackets around the denominator in your calculator
-19.72 ?
you should get -19.7 degrees. So the milk's temperature decrease by 19.7 degrees C
thank you so much
no problem :)
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