Question

∼[(q ∧ r) → (∼p ∨ r)]
This is false correct?

Answer 1

yes
do u know why?

Answer 2

Not at all. I just looked at the others like it and the answers were false! :( sad day here.

Answer 3

want me to show u?

Answer 4

Please. And thank you!

Answer 5

sorry i was busy with someone else
\[ \large \neg[(q\wedge r)\to(\neg p\vee r)]\equiv\neg[\neg(q\wedge r)\vee(\neg p\vee r)] \]
\[ \large \equiv\neg[(\neg q\vee\neg r)\vee(\neg p\vee r)] \]
\[ \large \equiv\neg[\neg q\vee \neg p\vee (\neg r\vee r)] \]
\[ \large \equiv\neg[\neg q\vee\neg p\vee\mathbb{V}] \]
\[ \large \equiv\neg[\mathbb{V}]\equiv\mathbb{F} \]