Question

Please help! Click attached!

Answer 1

Hint: Use the identity

\[\Large \tan(A+B) = \frac{\tan(A)+\tan(B)}{1-\tan(A)\tan(B)}\]

btw, I'm looking up identities here: http://www.sosmath.com/trig/Trig5/trig5/trig5.html

Answer 2

still have my sheet handy? http://learnix.net/ultimate-trig-cheat-sheet/

Answer 3

the above angle sum formula is exactly what you need?

Answer 4

Well I just the second step as shown in the image attached. @agentc0re

Answer 5

*I just need

Answer 6

@jim_thompson5910 Thank you for the link!

Answer 7

You're welcome

Compare the identity

\[\Large \tan(A+B) = \frac{\tan(A)+\tan(B)}{1-\tan(A)\tan(B)}\]

with

\[\Large \frac{\tan(24)+\tan(21)}{1-\tan(24)\tan(21)}\]


So we can see A = 24 and B = 21. I'm sure you know what to do from here.

Answer 8

well you find the value from the first step.. That value is Equal to 1 divided by the first step. make sense?

Answer 9

So a.?

Answer 10

no

Answer 11

if you type choice A into a calculator, and you compare that with what you get when you type in the original expression into a calculator, you'll see that the two are NOT the same

Answer 12

oh wait, in this special case, they are the same...oh well, nvm that last comment

But in general, they won't be

Answer 13

ex:

if it were 24 and 22, then it would be different

Answer 14

Oh I see

Answer 15

c.!

Answer 16

They match!

Answer 17

you nailed it

Answer 18

Great job! :D

Answer 19

AWESOME! Thanks!

Answer 20

yw