Question

Put the equation below in the form ax2 + bx + c = 0. Enter exponents using the caret ( ^ ). For example, you would enter 4x2 as 4x^2.

(x + 3)2 + 4x = 0

Answer 1

@jim_thompson5910
can you help me please?

Answer 2

(a+b)^2 = (a+b)(a+b)

(a+b)^2 = a(a+b)+b(a+b)

(a+b)^2 = a^2+ab+ab+b^2

(a+b)^2 = a^2+2ab+b^2

Answer 3

So for example (not this problem, but something similar)

If a = x and b = 7, then


(a+b)^2 = a^2+2ab+b^2

(x+7)^2 = x^2+2x*7+7^2

(x+7)^2 = x^2+14x+49

Answer 4

x^2+6x+9

Answer 5

good, so

(x + 3)^2 = x^2+6x+9

Now add 4x to both sides and tell me what you get

Answer 6

4x^3+10x^2+15x+0
i feel like i did that wrong.

Answer 7

6x+4x = ???

Answer 8

10x

Answer 9

So

(x + 3)^2 = x^2+6x+9

(x + 3)^2 + 4x = x^2+6x+9 + 4x ... Add 4x to both sides.

(x + 3)^2 + 4x = x^2 + (6x+4x) + 9

(x + 3)^2 + 4x = x^2 + (10x) + 9

(x + 3)^2 + 4x = x^2 + 10x + 9


Making sense?

Answer 10

x^2+9+4x=2x^2+10x+9

x^2+5x=0?

Answer 11

how are you getting that?

Answer 12

oh is this a whole new problem???

Answer 13

im soo confused

Answer 14

did you just post a whole new problem?

Answer 15

no

Answer 16

oh, then i have no idea how you got that

Answer 17

i dont either i dont know what im doing.

Answer 18

do you see how I got

(x + 3)^2 + 4x = x^2 + 10x + 9

???

Answer 19

no.

Answer 20

(step 1) (x + 3)^2 = x^2+6x+9

(step 2) (x + 3)^2 + 4x = x^2+6x+9 + 4x ... Add 4x to both sides.

(step 3) (x + 3)^2 + 4x = x^2 + (6x+4x) + 9

(step 4) (x + 3)^2 + 4x = x^2 + (10x) + 9

(step 5) (x + 3)^2 + 4x = x^2 + 10x + 9

Tell me which step you're stuck at