Angle A in Quadrant III and 0°≤A<360°, cosA= -2/5 cos A/2= a. √7/10 b. √3/10 c. -√3/10 d. -√7/10
It's given that A is in third quadrant, so A would lie between 180 and 270 degrees \[180\le A \le 270\] Can you tell the range of A/2 ?
Oh o.k. Wait, the range of A/2?
yeah, like A is from 180 to 270 what would be for A/2?
90 to 135?
good, so what's the sign of cosine in this range?
@mathsux4real what's the sign of cos in II quadrant?
cos(θ) < 0 ?
good:) so here we would have cos A/2 <0 do yo know the half angle formula for cosine?
Can you give it to me? I don't know it right off the bat
it's given as \[\Large 2 \cos^2 \frac A 2=1+ \cos A\]
find cos A/2 and remember that it's negative
I can't seem to match it up.
put cos A=-2/5 I think you'd get it. Try again :)
So 0.6
it's \[2\times \cos^2 \frac A 2=1+\cos A\] you have to divide by 2 and then take root
I came up with either 1.825 or 1.35 :/
@dta255 any thoughts?
\[2\times \cos^2 \frac A 2=1-\frac 25\] \[2\times \cos^2 \frac A 2=\frac 35\] divide both sides by 2, we get \[ \cos^2 \frac A 2=\frac 3{10}\] Taking root both sides, we get \[ \cos \frac A 2=\pm \sqrt {\frac {3}{10}}\] Now which sign should we take
+
@mathsux4real here \[\frac A 2\] lies in the second quadrant, then what will be the sign?
-
yes:) do you understand this?
Yes. I looked it up to understand fully. Thank you very much ash
welcome:D
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